Learn how to manage

Littlefield Assignment Details, Game 1

Game number: 1 Objective is to learn how to manage: Capacity Changes you can make in the game:

1. Buy and sell machines? Yes 2. Change priority at station 2? Yes 3. Change lot size? No 4. Change pricing contract? No 5. Limit WIP? No 6. Change re-order point and quantity? No 7. Take out loan? (If yes, day available) No

Starting Conditions 1. Number of machines

At station 1 1 At station 2 1 At station 3 1 Machine cost at station 1 ($ 000) 100 Machine cost at station 2 ($ 000) 100 Machine cost at station 3 ($ 000) 100

2. Priority at station 2 FIFO 3. Kits/job (starting lot size = 1 lot / job) 60

Setup time at station 1, hours/lot 0 Setup time at station 2, hours/lot 0 Setup time at station 3, hours/lot 0

4. Number of pricing contracts 1 Contract 1: max. revenue per order, $ 400 Contract 1: quoted/max lead time, days 0.2/0.4 Contract 2: max. revenue per order, $ – Contract 2: quoted/max lead time, days – Contract 3: max. revenue per order, $ – Contract 3: quoted/max lead time, days –

5. WIP limit 50 6. Re-order point, kits 0

Re-order quantity, kits 120 Lead time for raw materials order, days 0 Cost of raw materials per kit, $ 0 Fixed order cost, $ 0 Holding Cost, % /yr.(excluding interest) 0

7. Interest rate gained on cash, % / yr 0 Debt initial cost (% of debt incurred) – Debt interest rate, % / yr –

Demand (if trend, see note below) Is there a trend in the Demand? Yes (See note on next page) (1)

Notes regarding demand: (1) Demand will increase roughly linearly from day 1 until the end of the game (day 270).

Good luck in the game! Here is a quick summary of the first game. Game 1: Learning objective: help you learn how to manage capacity as a function of demand.

Demand: demand will increase roughly linearly from day 0 to day 270. Possible moves: you will be able to buy machines at all stations, and change priority at station 2. Lead time: you must complete the job in 0.2 days or less to get full revenue of $400 per job. If you don’t get your jobs done within 0.4 days, you don’t get any money.

Run1

jobs jobs Raw mtl Utilization Queue (kits) jobs Lead Rev/ Analysis based on the first 50 days Raw mtl. Inventory
Day rejected accepted inv, kits Sta 1 Sta 2 Sta 3 RM Sta 1 Sta 2 Sta 3 done Time job
1 – 0 1 – 0 – 0 – 0 – 0 – 0 – 0 – 0 0 – 0 $1,000 col. D: I=
2 – 0 1 0.05 0.03 0.07 – 0 – 0 – 0 – 0 2 0.074 $1,000
3 – 0 2 0.05 0.03 0.07 – 0 – 0 – 0 – 0 2 0.074 $1,000
4 – 0 2 0.05 0.03 0.07 – 0 – 0 – 0 – 0 2 0.074 $1,000 m= 1 m= 1 m= 1
5 – 0 3 0.06 0.03 0.07 – 0 – 0 – 0 – 0 2 0.074 $1,000
6 – 0 2 0.07 0.04 0.10 – 0 – 0 – 0 – 0 3 0.074 $1,000 Job Arrives WIP<limit, Job matched Job is
7 – 0 4 0.10 0.06 0.14 – 0 – 0 – 0 – 0 4 0.074 $1,000 Check WIP Job is with RM and finished
8 – 0 4 0.08 0.04 0.10 – 0 – 0 – 0 – 0 3 0.074 $1,000 accepted split into “b” lots
9 – 0 4 0.12 0.06 0.14 – 0 – 0 – 0 – 0 4 0.074 $1,000 Job waits Job (lot) waits Job (lot) waits Job (lot) waits Lot waits until all
10 – 0 4 0.11 0.07 0.17 – 0 – 0 – 0 – 0 5 0.074 $1,000 WIP=limit, for RM for empty Lot processed for empty Lot processed for empty Lot processed lots of job are done
11 – 0 5 0.13 0.07 0.17 – 0 – 0 – 0 – 0 4 0.074 $1,000 Job is rejected machine-1 at station 1 machine-2 at station 2 machine-3 at station 3 (no wait if 1 lot/job)
12 – 0 5 0.13 0.08 0.17 – 0 – 0 – 0 – 0 6 0.074 $1,000 Rates column B: col. C: R= col. L: R=
13 – 0 6 0.14 0.07 0.17 – 0 – 0 – 0 – 0 5 0.074 $1,000 jobs/day
14 – 0 6 0.14 0.09 0.21 – 0 – 0 – 0 – 0 6 0.074 $1,000
15 – 0 6 0.17 0.09 0.23 – 0 – 0 – 0 – 0 6 0.074 $1,000 utilizations, u col. E: u1= col. F: u2= col. G: u3=
16 – 0 6 0.15 0.10 0.22 – 0 – 0 – 0 – 0 7 0.074 $1,000
17 – 0 8 0.18 0.10 0.24 – 0 – 0 – 0 – 0 7 0.074 $1,000
18 – 0 7 0.20 0.10 0.27 – 0 – 0 – 0 – 0 7 0.074 $1,000 Number in system (WIP): H: Iq-RM= I: Iq-1= I1=mu1 J: Iq-2= I2=mu2 K: Iq-3= I3=mu3 WIP=sum
19 – 0 8 0.20 0.12 0.25 – 0 – 0 – 0 – 0 8 0.074 $1,000
20 – 0 8 0.20 0.12 0.29 – 0 – 0 – 0 – 0 8 0.074 $1,000 Contract lead time limits
21 – 0 8 0.20 0.13 0.30 – 0 – 0 – 0 – 0 9 0.074 $1,000 Time in system (days): Tq-RM= Tq=Iq/R p=um/R Tq=Iq/R p=um/R Tq=Iq/R p=um/R Col. M: T= T=sum Contract 1
22 – 0 9 0.23 0.13 0.31 – 0 – 0 – 0 – 0 9 0.074 $1,000 0.4
23 – 0 9 0.23 0.13 0.31 – 0 – 0 – 0 – 0 9 0.074 $1,000 Col. N, avg revenue: $ 1,000
24 – 0 10 0.25 0.13 0.34 – 0 – 0 – 0 – 0 9 0.074 $1,000 Capacity of system (jobs/day) m c= m / p m c= m / p m c= m / p minimum
25 – 0 10 0.25 0.15 0.34 – 0 – 0 – 0 – 0 10 0.074 $1,000
26 – 0 10 0.25 0.16 0.36 – 0 – 0 – 0 – 0 11 0.074 $1,000
27 – 0 11 0.28 0.15 0.37 – 0 – 0 – 0 – 0 10 0.074 $1,000
28 – 0 11 0.28 0.16 0.39 – 0 – 0 – 0 – 0 11 0.074 $1,000
29 – 0 12 0.28 0.18 0.38 – 0 – 0 – 0 – 0 12 0.074 $1,000
30 – 0 11 0.29 0.18 0.42 – 0 – 0 – 0 – 0 12 0.074 $1,000
31 – 0 13 0.31 0.18 0.42 – 0 – 0 – 0 – 0 12 0.074 $1,000
32 – 0 12 0.32 0.18 0.44 – 0 – 0 – 0 – 0 12 0.074 $1,000
33 – 0 13 0.33 0.19 0.44 – 0 – 0 – 0 – 0 13 0.074 $1,000
34 – 0 13 0.33 0.19 0.47 – 0 – 0 – 0 – 0 13 0.074 $1,000
35 – 0 14 0.35 0.20 0.46 – 0 – 0 – 0 – 0 14 0.074 $1,000
36 – 0 14 0.35 0.20 0.49 – 0 – 0 – 0 – 0 14 0.074 $1,000
37 – 0 14 0.35 0.21 0.51 – 0 – 0 – 0 – 0 14 0.074 $1,000
38 – 0 15 0.38 0.22 0.51 – 0 – 0 – 0 – 0 15 0.074 $1,000
39 – 0 15 0.38 0.22 0.53 – 0 – 0 – 0 – 0 15 0.074 $1,000
40 – 0 16 0.39 0.23 0.53 – 0 – 0 – 0 – 0 16 0.074 $1,000
41 – 0 16 0.39 0.23 0.56 – 0 – 0 – 0 – 0 15 0.074 $1,000
42 – 0 16 0.41 0.24 0.56 – 0 – 0 – 0 – 0 17 0.074 $1,000
43 – 0 16 0.40 0.23 0.59 – 0 – 0 – 0 – 0 16 0.074 $1,000
44 – 0 17 0.43 0.25 0.59 – 0 – 0 – 0 – 0 17 0.074 $1,000
45 – 0 18 0.44 0.26 0.60 – 0 – 0 – 0 – 0 17 0.074 $1,000
46 – 0 17 0.44 0.25 0.62 – 0 – 0 – 0 – 0 18 0.074 $1,000
47 – 0 18 0.45 0.26 0.63 – 0 – 0 – 0 – 0 18 0.074 $1,000
48 – 0 19 0.47 0.28 0.63 – 0 – 0 – 0 – 0 19 0.074 $1,000
49 – 0 19 0.46 0.27 0.66 – 0 – 0 – 0 – 0 18 0.074 $1,000
50 – 0 19 0.48 0.28 0.66 – 0 – 0 – 0 – 0 19 0.074 $1,000