min-a1-b2-c4

min(a1+b2+c4)

If

$$

c>0

c>0, the real numbers

$$

a,b neq 0

a,b=0, when

$$

4a^2-2ab+b^2-c=0

4a2−2ab+b2−c=0, and

$$

|2a+b|

∣2a+b∣ is the maximum.

Find the minimum of

$$

left(dfrac1a+dfrac2b+dfrac4cright)

(a1+b2+c4)